Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.4 Area of a Triangle - 8.4 Assess Your Understanding - Page 544: 13

Answer

$9.56$ square units

Work Step by Step

By Heron's theorem $K=\sqrt{s(s-a)(s-b)(s-c)}$, where $s=\frac{a+b+c}{2}.$ Hence, $s=\frac{9+6+4}{2}=9.5$. Thus, $K=\sqrt{9.5(9.5-9)(9.5-6)(9.5-4)}\approx9.56.$
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