# Chapter 8 - Applications of Trigonometric Functions - 8.4 Area of a Triangle - 8.4 Assess Your Understanding - Page 544: 18

$10.39$ square units

#### Work Step by Step

By definition: $K=\frac{ab\cdot \sin(C)}{2}.$ Hence, here $K=\frac{6\cdot4\cdot \sin(60^o)}{2}\approx10.39.$

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