Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.4 Area of a Triangle - 8.4 Assess Your Understanding - Page 544: 12

Answer

$8.18$ square units

Work Step by Step

By Heron's theorem $K=\sqrt{s(s-a)(s-b)(s-c)}$, where $s=\frac{a+b+c}{2}.$ Hence here $s=\frac{4+5+8}{2}=8.5$ $K=\sqrt{8.5(8.5-4)(8.5-5)(8.5-8)}\approx8.18$
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