## Precalculus (10th Edition)

Published by Pearson

# Chapter 8 - Applications of Trigonometric Functions - 8.4 Area of a Triangle - 8.4 Assess Your Understanding - Page 544: 24

#### Answer

$2.83$ square units

#### Work Step by Step

By Heron's formula, $K=\sqrt{s(s-a)(s-b)(s-c)}$, where $s=\frac{a+b+c}{2}.$ Hence, $s=\frac{3+3+2}{2}=4$ Thus, $K=\sqrt{4(4-3)(4-3)(4-2)}\approx2.83.$

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