Answer
$19.90$ square units
Work Step by Step
By Heron's formula, $K=\sqrt{s(s-a)(s-b)(s-c)}$, where $s=\frac{a+b+c}{2}.$
Hence,
$s=\frac{5+8+9}{2}=11$
Thus,
$K=\sqrt{11(11-5)(11-8)(11-9)}\approx19.90.$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 8 - Applications of Trigonometric Functions - 8.4 Area of a Triangle - 8.4 Assess Your Understanding - Page 544: 25
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