Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.4 Area of a Triangle - 8.4 Assess Your Understanding - Page 544: 35

Answer

$9.03$ square feet

Work Step by Step

The Area of sector can be computed by the formula: $K=\frac{\theta}{360}\cdot \pi \cdot r^2$,where $\theta$ is in degrees Hence, $K_1=\frac{70}{360}\cdot \pi \cdot 8^2\approx39.10.$ By definition the area of a triangle is given by the formula: $K_2=\frac{ab\cdot \sin(C)}{2}.$ Hence, the area of the triangle is $K_2=\frac{8\cdot8\cdot \sin(70^o)}{2}\approx30.07.$ Thus, the area of the segment is: $K_1-K_2=39.10-30.07=9.03$
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