Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 394: 42

Answer

$tan\theta= -2\sqrt 2$, $cot\theta= -\frac{\sqrt 2}{4}$, $sec\theta= -3$, $csc\theta= \frac{3\sqrt 2}{4}$.

Work Step by Step

Given $sin\theta=\frac{2\sqrt 2}{3}, cos\theta=-\frac{1}{3}$, we have: $tan\theta=\frac{sin\theta}{cos\theta}=-2\sqrt 2$, $cot\theta=\frac{cos\theta}{sin\theta}=-\frac{\sqrt 2}{4}$, $sec\theta=\frac{1}{cos\theta}=-3$, $csc\theta=\frac{1}{sin\theta}=\frac{3\sqrt 2}{4}$.
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