Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding: 21

Answer

$0$

Work Step by Step

$\tan \alpha =\tan \left( \alpha -2\pi n\right) \\\Rightarrow \tan \left( 21\pi \right) =\tan \left( 21\pi -20\pi \right) \\=\tan \pi \\=\dfrac {\sin \pi }{\cos \pi } \\=\dfrac {0}{-1} \\=0$
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