Answer
$\text{Quadrant II}$
Work Step by Step
According to the image, $\sin{\theta}>0$ in Quadrants I and II.
$\cos{\theta} \lt 0$ in Quadrants II and III
Hence, the angle must be in Quadrant II.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 394: 27
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