Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 394: 37

Answer

$tan\theta= 2$, $cot\theta= \frac{1}{2}$, $sec\theta= \sqrt 5$, $csc\theta= \frac{\sqrt 5}{2}$.

Work Step by Step

Given $sin\theta=\frac{2\sqrt 5}{5}, cos\theta=\frac{\sqrt 5}{5}$, we have: $tan\theta=\frac{sin\theta}{cos\theta}=2$, $cot\theta=\frac{cos\theta}{sin\theta}=\frac{1}{2}$, $sec\theta=\frac{1}{cos\theta}=\sqrt 5$, $csc\theta=\frac{1}{sin\theta}=\frac{\sqrt 5}{2}$.
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