Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding: 24

Answer

$1$

Work Step by Step

$\cot \alpha =\cot \left( \alpha -2\pi k\right) \\\Rightarrow \cot \dfrac {17\pi }{4}=\cot \left( \dfrac {17\pi }{4}-4\pi \right) \\=\cot \dfrac {\pi }{4} \\=\dfrac {\cos \frac {\pi }{4}}{\sin \frac {\pi }{4}} \\=\dfrac {\frac {\sqrt {2}}{2}}{\frac {\sqrt {2}}{2}} \\=1$
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