Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding: 15

Answer

$1$

Work Step by Step

$\csc{\alpha} =\csc{\left( \alpha -360\right)} \Rightarrow \csc{450^o}=\csc{\left( 450^o-360^o\right)} =\csc{90^o}=\dfrac {1}{\sin {90^o}}=\dfrac {1}{1}=1$
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