Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding: 11

Answer

$\dfrac {\sqrt {2}}{2}$

Work Step by Step

$\sin \alpha =\sin \left( \alpha -360^o\right) \Rightarrow \sin \left( 405^o\right) =\sin \left( 405^o-360^o\right) =\sin {45^o}=\dfrac {\sqrt {2}}{2}$
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