Answer
$\dfrac {\sqrt {2}}{2}$
Work Step by Step
$\sin \alpha =\sin \left( \alpha -360^o\right) \Rightarrow \sin \left( 405^o\right) =\sin \left( 405^o-360^o\right) =\sin {45^o}=\dfrac {\sqrt {2}}{2}$
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