Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 394: 38

Answer

$tan\theta= \frac{1}{2}$, $cot\theta= 2$, $sec\theta= -\frac{\sqrt 5}{2}$, $csc\theta= -\sqrt 5$.

Work Step by Step

Given $sin\theta=-\frac{\sqrt 5}{5}, cos\theta=-\frac{2\sqrt 5}{5}$, we have: $tan\theta=\frac{sin\theta}{cos\theta}=\frac{1}{2}$, $cot\theta=\frac{cos\theta}{sin\theta}=2$, $sec\theta=\frac{1}{cos\theta}=-\frac{\sqrt 5}{2}$, $csc\theta=\frac{1}{sin\theta}=-\sqrt 5$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.