Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - 13.3 Probability - 13.3 Asses Your Understanding - Page 865: 34

Answer

$\dfrac{1}{2}$

Work Step by Step

We know that $\text{probability}=\dfrac{\text{number of favorable outcomes}}{\text{number of all outcomes}}=\dfrac{n(F)}{n(S)}.$ There are $5$ odd numbers in the sample space so $5$ outcomes favor the event $F$. There are a total of $10$ possible outcomes. Hence, $P(F)=\dfrac{5}{10}=\dfrac{1}{2}$
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