Answer
$\frac{1}{3}$.
Work Step by Step
$n(S)=2\cdot3=6$, because the third spinner can have $2$ outcomes and the second spinner can have $3$ outcomes.
$n(E)=2$, because either a forward followed by a yellow or a forward followed by a green are the required outcomes.
We know that $P(E)=\frac{n(E)}{n(S)}$, hence $P=\frac{2}{6}=\frac{1}{3}$.
