Answer
$\dfrac{3}{10}$
Work Step by Step
We know that $\text{probability}=\dfrac{\text{number of favourable outcomes}}{\text{number of all outcomes}}=\dfrac{n(E)}{n(S)}.$
There are $3$ outcomes that favor the event $E$ and there are a total of $10$ possible outcomes in all.
Hence,
$P(E)=\dfrac{3}{10}.$