Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - 13.3 Probability - 13.3 Asses Your Understanding - Page 865: 20

Answer

$\frac{1}{12}$.

Work Step by Step

$n(S)=3\cdot4\cdot2=24$, because the second spinner can have $3$ outcomes, the first spinner can have $4$ outcomes and the third spinner can have $2$ outcomes. $n(E)=2$, because either a yellow followed by a $2$ and a forward or a yellow followed by a $4$ and a forward are the required outcomes. We know that $P(E)=\frac{n(E)}{n(S)}$, hence $P=\frac{2}{24}=\frac{1}{12}$.
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