Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - 13.3 Probability - 13.3 Asses Your Understanding - Page 865: 29


$P(1)=P(3)=P(5)=\frac{2}{9}$, $P(2)=P(4)=P(6)=\frac{1}{9}.$

Work Step by Step

Here if the probability of getting an even number is $x$, then $P(2)=P(4)=P(6)=x$ and $P(1)=P(3)=P(5)=2x$. We know that $P(1)+P(2)+P(3)+P(4)+P(5)+P(6)=1\\2x+x+2x+x+2x+x=1\\9x=1\\x=\frac{1}{9}.$ Therefore $P(1)=P(3)=P(5)=\frac{2}{9}$, $P(2)=P(4)=P(6)=\frac{1}{9}.$
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