Answer
$\frac{1}{12}$.
Work Step by Step
$n(S)=4\cdot3\cdot2=24$, because the first spinner can have $4$ outcomes, the second spinner can have $3$ outcomes and the third spinner can have $2$ outcomes.
$n(E)=2$, because either a $1$ followed by a red and a backward or a $1$ followed by a green and a backward are the required outcomes.
We know that $P(E)=\frac{n(E)}{n(S)}$, hence $P=\frac{2}{24}=\frac{1}{12}$.
