Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - 13.3 Probability - 13.3 Asses Your Understanding - Page 865: 28

Answer

$P(T)=\frac{2}{3}$, $P(H)=\frac{1}{3}.$

Work Step by Step

If $T$=tails and $H$=heads, then if $P(H)=x$, then $P(T)=2x.$ We know that $P(T)+P(H)=1\\2x+x=1\\3x=1\\x=\frac{1}{3}.$ Therefore $P(T)=2x=\frac{2}{3}$, $P(H)=x=\frac{1}{3}.$
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