Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - 13.3 Probability - 13.3 Asses Your Understanding - Page 865: 30

Answer

$P(1)=P(3)=P(5)=P(2)=P(4)=\frac{1}{5}.$

Work Step by Step

Here if the probability of getting a non $6$ number is $x$, then $P(1)=P(3)=P(5)=P(2)=P(4)=x.$ We know that $P(1)+P(2)+P(3)+P(4)+P(5)=1\\x+x+x+x+x=1\\5x=1\\x=\frac{1}{5}.$ Therefore $P(1)=P(3)=P(5)=P(2)=P(4)=\frac{1}{5}.$
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