#### Answer

neither

#### Work Step by Step

In order for a sequence to be geometric, the quotient of all consecutive terms must be constant.
Hence, in the given sequence we have:
$\dfrac{a_2}{a_1}=\dfrac{\frac{3}{4}}{\frac{2}{3}}=\dfrac{9}{8}$
$\dfrac{a_3}{a_2}=\dfrac{\frac{4}{5}}{\frac{3}{4}}=\dfrac{16}{15}$
Since the quotient sare not the same, then the sequence is not geometric.
In order for a sequence to be arithmetic, the difference of all consecutive terms must be constant.
Hence, here we have:
$a_2-a_1=\dfrac{3}{4}-\dfrac{2}{3}=\dfrac{1}{12}$
$a_3-a_2=\dfrac{4}{5}-\dfrac{3}{4}=\dfrac{1}{20}$
The the difference is not constant, then the sequence us not an arithmetic sequence.
Thus, the sequence us neither arithmetic nor geometric.