Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - Chapter Review - Review Exercises - Page 838: 3

Answer

$a_1=3$ $a_2=2$ $a_3=\frac{4}{3}$ $a_4=\frac{8}{9}$ $a_5=\frac{16}{27}$

Work Step by Step

If $a_n=\frac{2}{3}a_{n-1}$ and $a_1=3$, then $a_2=\frac{2}{3}a_1=\frac{2}{3}3=2$ $a_3=\frac{2}{3}a_2=\frac{2}{3}2=\frac{4}{3}$ $a_4=\frac{2}{3}a_3=\frac{2}{3}\frac{4}{3}=\frac{8}{9}$ $a_5=\frac{2}{3}a_4=\frac{2}{3}\frac{8}{9}=\frac{16}{27}$
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