Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - Chapter Review - Review Exercises - Page 838: 2

Answer

$c_1=2$ $c_2=1$ $c_3=\frac{8}{9}$ $c_4=1$ $c_5=\frac{32}{25}$

Work Step by Step

If $\{c_n\}=\frac{2^n}{n^2}$, then $c_1=\frac{2^1}{1^2}=\frac{2}{1}=2$ $c_2=\frac{2^2}{2^2}=\frac{4}{4}=1$ $c_3=\frac{2^3}{3^2}=\frac{8}{9}$ $c_4=\frac{2^4}{4^2}=\frac{16}{16}=1$ $c_5=\frac{2^5}{5^2}=\frac{32}{25}$
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