Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - Chapter Review - Review Exercises - Page 838: 1


$a_1=-\frac{4}{3}$ $a_2=\frac{5}{4}$ $a_3=-\frac{6}{5}$ $a_4=\frac{7}{6}$ $a_5=-\frac{8}{7}$

Work Step by Step

If $\{a_n\}=(-1)^n\frac{n+3}{n+2}$, then $a_1=(-1)^1\frac{1+3}{1+2}=-\frac{4}{3}$ $a_2=(-1)^2\frac{2+3}{2+2}=\frac{5}{4}$ $a_3=(-1)^3\frac{3+3}{3+2}=-\frac{6}{5}$ $a_4=(-1)^4\frac{4+3}{4+2}=\frac{7}{6}$ $a_5=(-1)^5\frac{5+3}{5+2}=-\frac{8}{7}$
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