Answer
$\sum_{k=1}^{4} (4k+2)=6+10+14+18=48$
Work Step by Step
Expand by substituing $k=1$ to $k=4$ to obtain:
$\sum_{k=1}^{4} (4k+2)=(4(1)+2)+(4(2)+2)+(4(3)+2)+(4(4)+2)=6+10+14+18=48$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.