Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - Chapter Review - Review Exercises - Page 838: 4

Answer

$a_1=2$ $a_2=0$ $a_3=2$ $a_4=0$ $a_5=2$

Work Step by Step

If $a_n=2-a_{n-1}$ and $a_1=2$, then $a_2=2-a_1=2-2=0$ $a_3=2-a_2=2-0=2$ $a_4=2-a_3=2-2=0$ $a_5=2-a_4=2-0=2$
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