Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - Chapter Review - Review Exercises - Page 839: 13



Work Step by Step

I know that $\sum_{k=1}^{n} (k^2)=\frac{n(n+1)(2n+1)}{6}.$ Hence $\sum_{k=1}^{30} (k^2)=\frac{30(30+1)(2(30)+1)}{6}=9455$
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