Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - Chapter Review - Review Exercises - Page 839: 31

Answer

$81x^4-432x^3+864x^2-768x+256$

Work Step by Step

We are given the expression: $(3x-4)^4$ Expand the expression using the Binomial Theorem: $(3x-4)^4=\binom{4}{0}(3x)^4(-4)^0+\binom{4}{1}(3x)^3(-4)^1+\binom{4}{2}(3x)^2(-4)^2+\binom{4}{3}(3x)^1(-4)^3+\binom{4}{4}(3x)^0(-4)^4$ $=81x^4-4(27)x^3(4)+6(9)x^2(16)-4(3)x(64)+256$ $=81x^4-432x^3+864x^2-768x+256$
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