Answer
$35$
Work Step by Step
We know that $a_n=a_1+(n-1)d.$
where $d$=common difference and $a_1$= the first term
Here $a_1=3$ and $d=a_2-a_1=7-3=4$
Hence, here we have
$a_n=3+(n-1)\cdot4.$
Therefore $a_{9}=3+(9-1)\cdot4\\3+32\\=35.$