Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 63


$\sum_{k=0}^{6} (-1)^k(\frac{1}{3^k})$

Work Step by Step

We can see that this is the sum of the $6$ fractions in which the denominator is $1$ and in which the first numerator is $1$, and gets multiplied by $3$ in each term. Also, the term changes sign each time. Hence the summation formula is: $\sum_{k=0}^{6} (-1)^k(\frac{1}{3^k})$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.