Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 30

Answer

$\{s_n\}=\frac{2^n}{3^n}=(\frac{2}{3})^n$.

Work Step by Step

The pattern suggests that $\{s_n\}=\frac{2^n}{3^n}=(\frac{2}{3})^n$. Because the numerator begins at $2$ and we can see that it gets multiplied by $2$ at each element, and the denominator begins at $3$ and we can see that it gets multiplied by $3$ at each element.
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