Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 51

Answer

$=\frac{1}{2}+\frac{4}{2}+...+ \frac{n^2}{2}$

Work Step by Step

$\sum_{k=1}^{n} \frac{k^2}{2}=\frac{1^2}{2}+\frac{2^2}{2}+...+ \frac{n^2}{2}=\frac{1}{2}+\frac{4}{2}+...+ \frac{n^2}{2}$
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