## Precalculus (10th Edition)

$3,\dfrac{3}{2},\dfrac{1}{2},\dfrac{1}{8},\dfrac{1}{40}$
We are given the sequence: $a_1=3$ $a_n=\dfrac{a_{n-1}}{n}$ Determine the first 5 terms of the sequence by substituting 1, 2, 3, 4, 5 for $n$: $a_1=3$ $a_2=\dfrac{a_1}{2}=\dfrac{3}{2}$ $a_3=\dfrac{a_2}{3}=\dfrac{\dfrac{3}{2}}{3}=\dfrac{1}{2}$ $a_4=\dfrac{a_3}{4}=\dfrac{\dfrac{1}{2}}{4}=\dfrac{1}{8}$ $a_5=\dfrac{a_4}{5}=\dfrac{\dfrac{1}{8}}{5}=\dfrac{1}{40}$