Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 57



Work Step by Step

$\sum_{k=2}^{n} ((-1)^k\ln{k})=((-1)^2\ln{2})+((-1)^3\ln{3})+...+((-1)^n\ln{n})=\ln{2}-\ln{3}+...+(-1)^n\ln{n}$
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