Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 56

Answer

$1+3+...+(2n-1)$

Work Step by Step

$\sum_{k=0}^{n-1} (2k+1)=(2(0)+1)+(2(1)+1)+...+(2(n-1)+1)=1+3+...+(2n-1)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.