Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 62

Answer

$\sum_{k=1}^{12} (2k-1)$

Work Step by Step

We can see that this is the sum of the first $12$ odd numbers. Hence the summation formula is: $\sum_{k=1}^{12} (2k-1)$
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