Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 58



Work Step by Step

$\sum_{k=3}^{n} ((-1)^{k+1}2^k)=((-1)^{3+1}2^3)+((-1)^{4+1}2^4)+...+((-1)^{n+1}2^n)=8-16+...+(-1)^{n+1}2^n$
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