Answer
$$x=-\frac{4}{3},\:x=2$$
Work Step by Step
Solving the equation, we find:
$$\frac{\left(3x+4\right)\left(x-2\right)}{\left(x-5\right)\left(x-1\right)}=0 \\ \left(3x+4\right)\left(x-2\right)=0 \\ x=-\frac{4}{3},\:x=2$$
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