Chapter 3 - Quadratic Functions - Exercises for Skills for Factoring - Page 135: 76

$$p=-\frac{1}{2},\:p=-3,\:p=3$$

Work Step by Step

Solving the equation, we find: $$2p^3+p^2-18p-9=0 \\ \left(2p+1\right)\left(p+3\right)\left(p-3\right)=0 \\ p=-\frac{1}{2},\:p=-3,\:p=3$$

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