Answer
$$p=-\frac{1}{2},\:p=-3,\:p=3$$
Work Step by Step
Solving the equation, we find:
$$ 2p^3+p^2-18p-9=0 \\ \left(2p+1\right)\left(p+3\right)\left(p-3\right)=0 \\ p=-\frac{1}{2},\:p=-3,\:p=3$$
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 3 - Quadratic Functions - Exercises for Skills for Factoring - Page 135: 76
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