Answer
$$g=3,\:g=-2,\:g=2$$
Work Step by Step
Solving the equation, we find:
$$ g^3-3g^2-4g+12=0 \\ \left(g-3\right)\left(g+2\right)\left(g-2\right)=0 \\ g=3,\:g=-2,\:g=2$$
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 3 - Quadratic Functions - Exercises for Skills for Factoring - Page 135: 74
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