Answer
$$z=-\frac{7}{2}$$
Work Step by Step
Solving the equation, we find:
$$ \frac{2}{z-3}+\frac{7}{z^2-3z}=0 \\ \frac{2}{z-3}z\left(z-3\right)+\frac{7}{z^2-3z}z\left(z-3\right)=0 \\ 2z+7=0 \\ z=-\frac{7}{2}$$
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 3 - Quadratic Functions - Exercises for Skills for Factoring - Page 135: 85
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