Answer
$(-3,-5),(1,3)$
Work Step by Step
Substitute the expression $4-x^2$ for $y$ in the second equation.
$$
\begin{array}{r}
y-2 x=1 \\
4-x^2-2 x=1 \\
-x^2-2 x+3=0 \\
x^2+2 x-3=0\\
(x+3)(x-1)=0
\end{array}
$$
This gives $x=-3 \quad$ and $\quad y=4-(-3)^2=-5$ or
$x=1 \quad$ and $\quad y=4-1^2=3$
