Answer
$$n=1,\:n=3$$
Work Step by Step
Solving the equation, we find:
$$ n^2-2n-3=2n\left(n-3\right) \\ -n^2+4n-3=0 \\ n_{1,\:2}=\frac{-4\pm \sqrt{4^2-4\left(-1\right)\left(-3\right)}}{2\left(-1\right)} \\ n=1,\:n=3$$
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 3 - Quadratic Functions - Exercises for Skills for Factoring - Page 135: 77
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