Answer
$$t=3-\sqrt{6},\:t=3+\sqrt{6}$$
Work Step by Step
Solving the equation, we find:
$$ -16t^2+96t-48=0 \\ t_{1,\:2}=\frac{-96\pm \sqrt{96^2-4\left(-16\right)\left(-48\right)}}{2\left(-16\right)} \\ t=3-\sqrt{6},\:t=3+\sqrt{6}$$
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 3 - Quadratic Functions - Exercises for Skills for Factoring - Page 135: 81
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