Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 3 - Quadratic Functions - Exercises for Skills for Factoring - Page 135: 83

Answer

$$a=-10,\:a=-\frac{2\sqrt{5}}{5},\:a=\frac{2\sqrt{5}}{5}$$

Work Step by Step

Solving the equation, we find: $$ 5a^3+50a^2-4a-40=0 \\ \left(a+10\right)\left(\sqrt{5}a+2\right)\left(\sqrt{5}a-2\right)=0 \\ a=-10,\:a=-\frac{2\sqrt{5}}{5},\:a=\frac{2\sqrt{5}}{5}$$
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