Answer
$$p=\frac{7+\sqrt{3}}{2},\:p=\frac{7-\sqrt{3}}{2}$$
Work Step by Step
The quadratic formula states:
$$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
Thus, solving the equation, we find:
$$ p_{1,\:2}=\frac{-\left(-14\right)\pm \sqrt{\left(-14\right)^2-4\cdot \:2\cdot \:23}}{2\cdot \:2} \\ p=\frac{7+\sqrt{3}}{2},\:p=\frac{7-\sqrt{3}}{2}$$
