Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 3 - Quadratic Functions - Exercises for Skills for Completing the Square - Page 138: 35

Answer

$$q=\frac{-3+\sqrt{15}}{2},\:q=-\frac{3+\sqrt{15}}{2}$$

Work Step by Step

The quadratic formula states: $$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$ Thus, solving the equation, we find: $$ q_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2} \\ q=\frac{-3+\sqrt{15}}{2},\:q=-\frac{3+\sqrt{15}}{2}$$
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