Answer
$$y_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:2\cdot \:2}}{2\cdot \:2}$$
Work Step by Step
The quadratic formula states:
$$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
Thus, solving the equation, we find:
$$y_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:2\cdot \:2}}{2\cdot \:2} \\ y_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:2\cdot \:2}}{2\cdot \:2}$$
